King's Gambit
Tuesday, June 15, 2004
Solution To Problem Of The Day 2004-06-14
1. Qc3! forces mate in two. If 1...Qxf3 then 2.Qc1+ Ke4 3. Qc4#, and if 1...Kg5 then 2. f4+ Kxf4 3. Qe3# (2...Kh6 3. Qh8#, 2...Kh4 3. Qg3#).
1. Qc3! forces mate in two. If 1...Qxf3 then 2.Qc1+ Ke4 3. Qc4#, and if 1...Kg5 then 2. f4+ Kxf4 3. Qe3# (2...Kh6 3. Qh8#, 2...Kh4 3. Qg3#).
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Serious chess. Serious fun!
